I was looking at sample questions for CBSE board for 9th grade (http://papers.icbse.com/sample/ix/2011/4.pdf).
Here is a problem and the solution.
Question No. 23:
Find the value of x3 + y3 + 15xy - 125 when x+y=5
There are two ways to solve this. Let's do it the formal way first
Solution 1:
Since x+y=5, y=5-x. Substitute this in the 1st equation
x3 + y3 + 15xy - 125 = x3 + (5-x)3 +15x(5-x) - 125
=x3 + (53 - 3.52.x + 3.5.x2 - x3) + (75x - 15x2) - 125
(using the formula for (a-b)3 )
=x3 + 125 - 75x + 15x2 - x3 + 75x -15x2 - 125
= 0
Now let's go through an informal solution (note: this is just used to get a quick answer and it's not the "right" way...)
Solution 2:
Find the value of x3 + y3 + 15xy - 125 when x+y=5
Since there are two variables and x+y=5 with no other equation involving x and y, we may assume that it does not matter what the values of x and y are provided that x+y=5. So let's assume x=5, y=0
Substituting these values of x and y in the first equation we get,
x3 + y3 + 15xy - 125 = 53 + 0 + 0 - 125 = 0
voila!!!
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